Shane Lowry and Adam Scott each recorded holes-in-one during the final round of the Houston Open, providing a rare display of accuracy on the par-3s.
The final round of the PGA Tour’s 2026 Houston Open delivered a remarkable moment when two of professional golf’s most accomplished players each recorded aces within the same day of competition.
Shane Lowry struck first, holing his tee shot on the par-3 second hole playing at approximately 170 yards. The ace marked Lowry’s fourth career hole-in-one on the PGA Tour, a testament to his precision with the short irons throughout his professional career.
Later in the round, Adam Scott matched the feat when his tee shot found the cup on the 11th hole from 189 yards out. The achievement represented Scott’s third PGA Tour ace, adding another memorable moment to his decorated career.
A Rare Double Feature
While holes-in-one occur throughout the professional golf calendar, having two accomplished players ace consecutive par-3s during the same final round remains an uncommon occurrence. Both players demonstrated the combination of skill, course knowledge, and favorable conditions that make such shots possible at the highest levels of competition.
Lowry’s fourth career ace positions him among the PGA Tour’s more prolific hole-in-one makers, while Scott’s third reinforces his reputation for consistency and excellence across all facets of his game. The simultaneous success of both players on par-3s highlighted the technical demands and opportunities these holes present throughout a tournament.
Such moments, while individual achievements, contribute to the compelling narrative of professional golf tournaments and remind audiences of the skill required to compete at the PGA Tour level.
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